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Question

A 50 kg skydiver falls through the air and attains terminal velocity after some time. The drag force is a function of velocity given as Fdrag=bv2 where the negative sign denotes that the drag force is opposite to the direction of velocity. What is the terminal velocity of the skydiver (assuming the drag constant b is 0.2 kg/m)?

A
5 m/s
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B
50 m/s
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C
100 m/s
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D
250 m/s
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Solution

The correct option is B 50 m/s
When the body falling through the air attains terminal velocity, the drag force(FD) will be equal to the weight of the body.
a=0, when body reaches terminal velocity.
And density of air is too low for considering buoyant force.
FD=mg
or, bv2T=mg ...(i)
[Magnitude of drag force is bv2]
Terminal velocity vT=mgb=50×100.2
vT=50 m/s

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