A $50 V$ d.c power supply is used to charge a battery of eight lead accumulators, each of emf $2 V$ and internal resistance $1 / 8 Ω$ . The charging current also runs a motor connected in series with the battery. The resistance of the motor is $5 Ω$ and the steady current supply is $4 A$ . The chemical power stored in the battery is

64 W

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96 W

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16 W

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50 W

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Solution

The correct option is A $64 W$
Total voltage of battery with eight accumulators $= 2 \times 8 = 16 V$
Current flowing through battery $= 4 A$

$∴$ Power stroed in battery $= V I = 16 \times 4 = 64 W$

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The correct option is A 64WTotal voltage of battery with eight accumulators =2×8=16VCurrent flowing through battery =4A∴ Power stroed in battery =VI=16×4=64W

The correct option is A $64 W$
Total voltage of battery with eight accumulators $= 2 \times 8 = 16 V$
Current flowing through battery $= 4 A$

$∴$ Power stroed in battery $= V I = 16 \times 4 = 64 W$