A $500 k g$ horse pulls a cart of mass $1500 k g$ along a level road with an acceleration of $1 m s^{- 2}$ . If the coefficient of sliding friction is $0.2$ , then the force exerted by the horse in forward direction is

4500 N

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4000 N

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5000 N

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6000 N

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Solution

The correct option is A $4500 N$
Given that,

Mass of horse = $500$ kg

Mass of cart = $1500$ kg

Acceleration = $1$ m/s²

Friction coefficient = $0.2$

Now, the force by the horse

Net force in forward direction = Accelerating force + friction

$F = m a + μ m g$

Now, put the value

$F = m (a + μ g)$

$F = (1500) (1 + 0.2 \times 10)$

$F = 1500 \times 3$

$F = 4500 N$

Hence, the force exerted by the horse in forward direction is $4500$ N

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A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of 1 ms−2. If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is

A $500 k g$ horse pulls a cart of mass $1500 k g$ along a level road with an acceleration of $1 m s^{- 2}$ . If the coefficient of sliding friction is $0.2$ , then the force exerted by the horse in forward direction is