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Question

A 500 kg horse pulls a cart of mass 1500 kg along a level road with an acceleration of 1 ms2. If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is

A
4500 N
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B
4000 N
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C
5000 N
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D
6000 N
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Solution

The correct option is A 4500 N

Given that,

Mass of horse = 500 kg

Mass of cart = 1500 kg

Acceleration = 1 m/s2

Friction coefficient = 0.2

Now, the force by the horse

Net force in forward direction = Accelerating force + friction

F=ma+μmg

Now, put the value

F=m(a+μg)

F=(1500)(1+0.2×10)

F=1500×3

F=4500N

Hence, the force exerted by the horse in forward direction is 4500 N


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