A 500 kg rocket can be accelerated at a constant rate from rest to 1800 km/h in 2 sec. The magnitude of the required net force is .

450,000 N

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12,000 N

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125,000 N

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18,00,000 N

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Solution

The correct option is C 125,000 N
As we know,

$F = \frac{Δ p}{Δ t}$

$Δ P = m (v - u) = 500 v$

v = 1800 km/hr

= $\frac{1800 * 1000}{3600} m / s$

= 500 m/s

$∴ Δ P = 500 (500 - 0)$

= 250,000 kg m/s

$F = \frac{250, 000}{2} = 125, 000 N$

$F_{n e t} = 125, 000 N$

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