(a)
The area of a triangle with vertices D (x, 3x), B (−3, 5) and C (4, −2) is given below:
Area of ∆DBC =
Area of ∆DBC =
Similarly, the area of a triangle with vertices A (6, 3), B (−3, 5) and C (4, −2) is given below:
∆ABC =
∆ABC = sq units
Given:
∆DBC:∆ABC = 1:2