Question

A 6 volt battery is connected to the terminals of the three metre long wire of uniform thickness and the resistance of $100\Omega$. The difference of potential between two points on the wire separated by a distance of 50 cm will be

• A. 1.5V
• B. 3V
• C. 3.5V
• D. 1V

Answer 1

The correct option is D 1V

The potential drop across $3m$ will be $6V$.

Let the potential drop across $50cm$ be $E$.

Since, $\frac{E_q}{L_1}=\frac{E_2}{L_2}$

$⟹\frac{6}{3}=\frac{E}{0.5}$

$[E=2\times 0.5=1V]$