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Question

The resistance of 10m long potentiometer wire is 20Ω. It is connected in series with a 3V battery and 10Ω resistor. The potential difference between two points separated by distance 30cm is equal to _________.

A
0.02V
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B
0.06V
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C
0.1V
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D
1.2V
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Solution

The correct option is B 0.06V

Using Ohm's Law V=IR
Current in the circuit = VReq, And Req=(20+10)Ω
So, I=330=0.1A
Given that resistance of 10m long potential wire is 20Ω
Resistance of 30cm long wire = 20×3010×100=0.6Ω
Using Ohm's Law again, potential difference between two points = IR=0.1×0.6=0.06V.
Therefore, B is correct option.


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