A 60 kg man holding a 20 kg box rides on a skateboard at a speed of 7 m/s. He throws the box behind him, giving it a velocity of 5 m/s. with respect to the ground. What is his velocity after throwing the object?

8 m/s

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9 m/s

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10 m/s

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11 m/s

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12 m/s

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Solution

The correct option is E 11 m/s
Using the law of conservation of momentum,
$I n i t i a l m o m e n t u m = F i n a l m o m e n t u m (m_{1} + m_{2}) v = m_{1} v_{1} + m_{2} v_{2} (60 + 20) 7 = 60 v_{1} + 20 (- 5) T h u s, v e l o c i t y o f t h e m a n = \frac{80 \times 7 + 20 \times 5}{60} m / s = 11 m / s$

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