A skydiver does 300 J of work in 20 seconds. How much power does he spend?

12 KW

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15 W

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18 W

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20 W

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Solution

The correct option is B
15 W

Given, work done = 300 J

Time taken = 20 s

Power spent by the skydiver = $\frac{work done}{time}$
$= \frac{300 J}{20 s} = 15 W$

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