A 60 kg skydiver is moving at a terminal speed 40 m in 2 seconds. The skydiver is spending a power of ___ KW.

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Solution

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = Force $\times$ Displacement = mgh
$= (60 \times 10 \times 40) J$ where $g = 10 m s^{- 2}$
So, power spent in 2 seconds $= (60 \times 10 \times \frac{40}{2}) W$

= 12000 W
= 12 KW

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A 60 kg skydiver is moving at a terminal speed 40 m in 2 seconds. The skydiver is spending a power of ___ KW.

Power spent by the skydiver = work donetime Work done in 2 seconds = Force × Displacement = mgh =(60×10×40) J where g=10ms−2 So, power spent in 2 seconds =(60×10×402) W = 12000 W = 12 KW

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = Force $\times$ Displacement = mgh
$= (60 \times 10 \times 40) J$ where $g = 10 m s^{- 2}$
So, power spent in 2 seconds $= (60 \times 10 \times \frac{40}{2}) W$

= 12000 W
= 12 KW