A 60μF capacitor is connected to a 110V. 60Hz a.c. supply. Determine the rms value of the current in the circuit.
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Solution
Rms value of voltage Vrms=110V Frequency of AC source f=60Hz Capacitance C=60×10−6F Capacitive reactance XC=12πfC=12π×60×60×10−6=44.2Ω Rms value of current Irms=VrmsXC=11044.2=2.5A