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Question

A 600 W mercury lamp emits a monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second?
h=6.626×1034 Js;velocity of light =3×108 ms1

A
1021
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B
1022
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C
1020
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D
1019
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Solution

The correct option is A 1021
According to Planck's quantum theory, E=nhcλ
Where, E = energy of the radiation =600 W=600 J/s
n = number of photons emitted per second
h = Planck's constant =6.626×1034 J s
c = speed of light =3×108 m/s
λ = wavelength of the radiation =331.3 nm=331.3×109m

On subtituting the values in the equation and solving for n,
n=Eλh.c=600×331.3×1096.626×1034×3×108

On solving n=1×1021 photons/second

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