wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

a7b2c3d5=512. Find the minimum value of a7+2b2+2c3+2d5

A

32

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

56

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

48

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

32


a7b2c3d5=512=29
AMG.M
a7+2b2+2c3+2d544a72b22c32d5
a7+2b2+2c3+2d544212
a72b22c32d58.4
32


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Real Valued Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon