1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A 700 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water? Density of water =1 g/cm3.

A
700 cm3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
300 cm3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1000 cm3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
30 cm3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B 300 cm3The weight of the cube is balanced by the buoyant force. The buoyant force is equal to the weight of the water displaced. If V volume of the cube is inside the water, the weight of the displaced water =Vρ g, where ρ is the density of water. Thus, Vρg=700×g ⇒V=700ρ=700 cm3 The total volume of the cube =(10 cm)3=1000 cm3. ∴ The volume of cube outside the water is 1000 cm3−700 cm3=300 cm3

Suggest Corrections
0
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program