  Question

A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate: (a) the net accelerating force and (b) the acceleration of the train.

Solution

(a) 35000 N (b) 1.944 m/s2  (a)Force exerted by the engine, F = 40000 N Frictional force offered by the track, Ff = 5000 N Net accelerating force, Fa = F − Ff = 40000 − 5000 = 35000 N Hence, the net accelerating force is 35000 N. (b)Acceleration of the train = a The engine exerts a force of 40000 N on all the five wagons. Net accelerating force on the wagons, Fa = 35000 N Mass of the wagons, m = Mass of a wagon × Number of wagons Mass of a wagon = 2000 kg Number of wagons = 5 ∴ m = 2000 × 5 = 10000 kg Total mass of the train, M = m + mass of engine  = 10000 + 8000 = 18000 kg From Newton’s second law of motion: Fa = Ma Hence, the acceleration of the train is 1.944 m/s2. [[video:17194]] ScienceScience - NCERT SolutionsAll

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