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# 8000kg engine pulls a train of 5 wagons each of 2000 kg along a horizontal track. If engine exerts a force of 40000N and track offers friction of 5000N then calculate 1). Net accelerating force 2). Acceleration of train 3). Force of wagon 1 on wagon 2

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## Given, force of engine = 40000 N Force of friction = 5000 N Mass of engine = 8000 kg Total weight of wagons = 5 x 2000 kg = 10000 kg (a) The net accelerating force = Force exerted by engine – Force of fricition = 40000 N – 5000 N = 35000 N (b) The acceleration of the train We know that, F = mass x acceleration Or, 35000 N = (mass of engine + mass of 5 wagons) X a Or, 35000 N = (8000 kg + 10000 kg) X a Or, 35000N = 18000 kg X a ⇒a=35000N18000 kg=1.944ms−2⇒a=35000N18000 kg=1.944ms-2 (c) The force of wagon 1 on wagon 2 = mass of four wagons x acceleration ⇒F=4×2000 kg×1.944ms−2⇒F=4×2000 kg×1.944ms-2 ⇒F=8000 kg×1.944ms−2⇒F=8000 kg×1.944ms-2 ⇒F=1552N⇒F=1552N Thus, (a) The net accelerating force = 35000N (b) The acceleration of train = 1.944 ms–2 (c) The force of wagon 1 on 2 = 1552 N  Suggest Corrections  7      Similar questions  Related Videos   Acceleration
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