A 8000 kg engine pulls a train of 5 wagons each of 2000 kg along a horizontal track. If the engine exerts a force of 40000 N and track offers a friction force of 5000N then calculate the force of wagon 1 on wagon 2.

Open in App

Solution

(c) Mass of all the wagons except wagon 1 is 4×2000 = 8000 kg
Acceleration of the wagons = 3.5 m/s2
Thus, force exerted on all the wagons except wagon 1 = 8000×3.5 = 28000 N
Therefore, the force exerted by wagon 1 on the remaining four wagons is 28000 N.
Hence, the force exerted by wagon 1 on wagon 2 is 28000 N.

We found a similar question to the one that you posted. Please check it out here.

Suggest Corrections

Similar questions

Q. A 8000 kg engine pulls a train of 5 wagons ,each of 2000 kg , along a horizontal track. If the engine exerts a force of 40000N and the track offers a friction force of 5000 N , then calculate the force of wagon 1 and wagon 2

Q. Question 7 (c)
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
(c) the force of wagon 1 on wagon 2.

Q. 8000kg engine pulls a train of 5 wagons each of 2000 kg along a horizontal track. If engine exerts a force of 40000N and track offers friction of 5000N then calculate
1). Net accelerating force
2). Acceleration of train
3). Force of wagon 1 on wagon 2

A 8000kg engine pulls a train of 5 wagons, each of 2000kg along a horizontal track. If the engine exerts a force of 40000N and the track offers a friction force of 5000N. Then calculate

1)the net accelerating force;

2)the acceleration of the train ;and

3) the force of wagon 1on wagon 2.

Q. Question 7 (a)
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
(a) the net accelerating force;

Join BYJU'S Learning Program