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# A 8000 kg engine pulls a train of 5 wagons ,each of 2000 kg , along a horizontal track. If the engine exerts a force of 40000N and the track offers a friction force of 5000 N , then calculate the force of wagon 1 and wagon 2

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## Answer: Given, force of engine = 40000 N Force of friction = 5000 N Mass of engine = 8000 kg Total weight of wagons = 5 x 2000 kg = 10000 kg The net accelerating force = Force exerted by engine – Force of fricition = 40000 N – 5000 N = 35000 N ⇒a=35000N18000 kg=1.944ms-2 The force of wagon 1 on wagon 2 Since, net accelerating force = 35000 N Mass of all 5 wagons = 10000 kg We know that, F = m x a Therefore, 35000N = 10000 kg x a ⇒a=35000N10000 kg=3.5ms−2⇒a=35000N10000 kg=3.5ms-2 Therefore, acceleration of wagons =3.5m/s2=3.5m/s2 Thus, force of wagon 1 on 2 = mass of four wagons x acceleration ⇒F=4×2000 kg×3.5ms−2⇒F=4×2000 kg×3.5ms-2 ⇒F=8000 kg×3.5ms−2⇒F=8000 kg×3.5ms-2 ⇒F=28000N  Suggest Corrections  0      Similar questions  Related Videos   Acceleration
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