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Question

A 8000kg engine pulls a train of 5 wagons, each of 2000kg along a horizontal track. If the engine exerts a force of 40000N and the track offers a friction force of 5000N. Then calculate 1)the net accelerating force; 2)the acceleration of the train ;and 3) the force of wagon 1on wagon 2.

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Solution

Mass of the engine = 8000 kg Mass of each wagon = 2000 kg, Np. of wagons = 5 mass of total wagon=2000×5 =10000 Total mass of train = 8000+(2000×5)=18000 Force, F = 40000 N Track resistance , R = 5000 N Total accelerating force = F −R =40000−5000=35000 Let acceleration = y m/s² Acceleration = Accelerating force / mass y=35000/18000 ​​​ = 35/18 =1.94 m/s² Frictional resistance of 4 wagons =5000×(2000×4)/18000 =2222 .22 N Accelerating force on 4 wagons =2000×4×1.944 =15552 N Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance =2222 .22 +15552=17774.22 N So, The net accelerating force=35000 The acceleration of the train=1.94 m/s² The force of wagon 1on wagon 2=17774.22 N

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