A $90^{\circ}$ elbow bend pipe diameter is 100 mm and loss coefficient is 0.9. Pipe friction factor is 0.02. What is the equivalent length of the pipe?

9 m

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2.25 m

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1.125 m

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4.5 m

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Solution

The correct option is D 4.5 m
Equivalent length of pipe $(L_{e})$ concept :

$H_{b e n d} = h_{f r i c t i o n l o s s}$

$K_{B} . \frac{V^{2}}{2 g} = \frac{f . L . V^{2}}{2 g D}$

$K_{B} = \frac{f L}{D}$

$∴ L = \frac{D . K_{B}}{f}$

$∴ Equivalent length (L_{e}) = \frac{0.1 \times 0.9}{0.02}$

$= 4.5 m$

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A 90∘ elbow bend pipe diameter is 100 mm and loss coefficient is 0.9. Pipe friction factor is 0.02. What is the equivalent length of the pipe?

The correct option is D 4.5 mEquivalent length of pipe (Le) concept : Hbend=hfriction loss KB.V22g=f.L.V22gD KB=fLD ∴L=D.KBf ∴Equivalent length (Le)=0.1×0.90.02 =4.5 m

A $90^{\circ}$ elbow bend pipe diameter is 100 mm and loss coefficient is 0.9. Pipe friction factor is 0.02. What is the equivalent length of the pipe?