Question

A ${}_{92}{U}^{235}$ reactor takes $30$ days to use $2kg$ of fuel and each fission gives $185MeV$ of energy. Then,the rate of fission is (N$=$ Avogadro's number)

• A. $\frac{2000N{s}^{-1}}{235\times 30\times 24\times 60\times 60}$
• B. $\frac{2\times 235N{s}^{-1}}{30\times 24\times 60\times 60}$
• C. $2N\times 235\times 30\times 24\times 60\times 60s^{-1}$
• D. $\frac{2\times 235\times 30\times 24\times 60\times 60}{N}{s}^{-1}$

Answer 1

The correct option is A $\frac{2000N{s}^{-1}}{235\times 30\times 24\times 60\times 60}$

Total no. of nuclei going under fission $=\frac{2000\times N}{235}$

Total time in secs $=30\times 24\times 60\times 60$ secs

Rate $=\frac{2000N/s}{235\times 30\times 60\times 60}$