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Concentration Terms

A 999.6 mg sa...

Question

A $999.6 mg$ sample of a pure organic compound containing chlorine is fused with $N a_{2} O_{2}$ to convert chlorine to $N a C l$ . The sample is then dissolved in water, and the chloride precipitated with $A g N O_{3},$ giving $1951.6 mg$ of $A g C l$ . If the molecular weight of organic compound is $147 u$ , how many chlorine atoms does each molecule contain?

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Solution

Moles of $A g C l$ = moles of chloride ( $C l^{-})$
$= \frac{1.9516}{143.5}$
Moles of organic compound
$= \frac{0.9996}{147}$
Chlorine atoms in each molecule of organic compound
$= \frac{\frac{1.9516}{143.5}}{\frac{0.9996}{147}} = 2$

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