Question

A 9m span simply supported beam AB supports a train of point loads as shown below.

The maximum positive shear force at one-third span from end 'A' is

• A. 69 kN
• B. 52.84 kN
• C. 66.67 kN
• D. 45 kN

Answer 1

The correct option is D 45 kN

Let us first of all draw ILD for shear at one-third span from end A.

For the SF to be maximum positive, the trailing load 50 kN should be placed at ‘C’.
$\therefore (V_C{)}_{max}=50\times \frac{2}{3}+20\times \frac{4}{9}+10\times \frac{2.5}{9}=45kN$