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B
P(A)>P(¯¯¯¯B)
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C
P(A)<P(B)
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D
P(A)=P(B)
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Solution
The correct option is AP(A)≤P(¯¯¯¯B) If A and B are mutually exclusive this simply meansP(A∩B)=ϕ⇒P(A∪B)≤1⇒P(A)+P(B)−P(A∩B)≤1P(A∩B)=0,∵(A∩B)=ϕ⇒P(A)≤1−P(B)⇒P(A)≤P(¯¯¯¯B)