A and B have 460 coins altogether. If 34 of A's number of coins is equal to 25 of B's number of coins, find how many coins must B give to A, so that they both have equal number of coins.
A
50
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B
70
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C
20
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D
90
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Solution
The correct option is C70 Let A's number of coins =x, so B's number of coins =460−x
34 of A=25 of B
34x=25(460−x)
∴15x=8(460−x)15x=3680−8x23x=3680x=160
A's number of coins = 160 coins
B's number of coins = 460−x=300 coins
So, B has to give A, 70 coins, so they both have equal number of coins. which is 230 coins each.