Question

In how many ways can a person having $3$ coins of $25$ paise, $4$ coins of $50$ paise and $2$ coins of one rupee give none or some coins to a beggar?

• A. $50$
• B. $25$
• C. $60$
• D. $64$

Answer 1

The correct option is C $60$

He has $3-25$ paise coins, $4-50$ paise coins and $2-1$ rupee coins.

No. of permutations is given by $(p+1)(q+1)(r+1)$

Where $p,q,\xi$ $r$ are different things containing identical items.

Total $=(3+1)(4+1)(2+1)$

$=4\times 5\times 3$

$=60.$

Hence, the answer is $60.$