A and B start from the same place- in the same direction and at the same time with speeds 6kmph and 2mrespectively-After 5 hours who will be ahead and by how much-

A's speed =6 kmph B's speed =2 mcovered by A in 5 hours =6× 5=30 kmand distance covered by B in 5 hours =5× 6 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Properties of Measures of Central Tendency

A and B sta...

Question

$A$ and $B$ start from the same place, in the same direction and at the same time with speeds $6$ kmph and $2$ m\sec respectively.After $5$ hours who will be ahead and by how much?

Open in App

Solution

$A^{'} s$ speed $= 6$ kmph
$B^{'} s$ speed $= 2$ m\sec
Distance covered by $A$ in $5$ hours $= 6 \times 5 = 30$ km
and distance covered by $B$ in $5$ hours $= 5 \times 60 \times 60 \times 2 = 36, 000$ m
$= \frac{36, 000}{1000} = 36$ km
$B$ will be ahead and $36 - 30 = 6$ km ahead.

Suggest Corrections

Similar questions

A

and

B

start from the same point and at the same time with speeds

15

kmph and

12

kmph respectively.Find the distance between

A

and

B

after

6

hours if both move in:

(i)

same direction

(i i)

the opposite directions.

A and B start at the same time from two places 30 km apart. If they walk in the same direction, A overtakes B in 10 hours and if they walk in opposite directions they meet in 2 hours. Find the rate of walking of A.

Q. Two cars start together in the same direction from the same place. The first car goes at uniform speed of

10

kmph. The second car goes at a speed of

8

kmph in the first hour and thereafter increasing the speed by

0.5

kmph each succeeding hour. After how many hours will the two cars meet?

Q. Two cars start together in the same direction and the same place .The first goes with a speed of 10kmph and the second goes with the speed of 8kmph in the first hour and increases the speed by 0.5 kmph in every succeeding hour after how many hours will the second car overtake the first car if both go non stop.

Q. Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much more time Car B will be 20Km ahead of Car A?

Join BYJU'S Learning Program

A and B start from the same place, in the same direction and at the same time with speeds 6kmph and 2m\sec respectively.After 5 hours who will be ahead and by how much?

A′s speed=6kmphB′s speed=2m\secDistance covered by A in 5 hours=6×5=30kmand distance covered by B in 5 hours=5×60×60×2=36,000m=36,0001000=36kmB will be ahead and 36−30=6km ahead.

$A$ and $B$ start from the same place, in the same direction and at the same time with speeds $6$ kmph and $2$ m\sec respectively.After $5$ hours who will be ahead and by how much?

$A^{'} s$ speed $= 6$ kmph
$B^{'} s$ speed $= 2$ m\sec
Distance covered by $A$ in $5$ hours $= 6 \times 5 = 30$ km
and distance covered by $B$ in $5$ hours $= 5 \times 60 \times 60 \times 2 = 36, 000$ m
$= \frac{36, 000}{1000} = 36$ km
$B$ will be ahead and $36 - 30 = 6$ km ahead.