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Inversely Proportional

Car A leaves ...

Question

Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much more time Car B will be 20Km ahead of Car A?

5 Hours

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6 Hours

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8 Hours

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11 Hours

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Solution

The correct option is B 6 Hours
20 =40(t-5) – 20t
T = 11
11-5 = 6

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Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much more time Car B will be 20Km ahead of Car A?

The correct option is B 6 Hours20 =40*(t-5) – 20*t T = 11 11-5 = 6

The correct option is B 6 Hours
20 =40(t-5) – 20t
T = 11
11-5 = 6