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Classical Definition of Probability

A and B throw...

Question

A and B throw a pair of dice. If A throws 9, find B's chance of throwing a higher number.

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Solution

A throws 9 and B throws a higher number Thus, B throws 10, 11 or 12

Total number of outcomes = $6 \times 6 \times 36$

Number of favourable outcomes = 6 [(4, 6), (5, 5), (6, 4), (5, 6), (6, 5), (6, 6)]

$∴$ P(B throwing a number greater than 9

$= \frac{6}{36} = \frac{1}{6}$

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