The correct option is C (a + b)2 (a b)^2 = a^2 2ab + b^2 (a b)^2 + 4ab = a^2 2ab + b^2 + 4ab = a^2 + 2ab + b^2 =(a + b)^2 ...

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Common Ratio

a-b2+4 a b=

Question

${(a - b)}^{2}$ + 4ab = ___________ .

a² + b²

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(a + b)²

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a² – b²

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a² – b²+ 4ab

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Solution

The correct option is B
(a + b)²

${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$

${(a - b)}^{2} + 4 a b = a^{2} - 2 a b + b^{2} + 4 a b$

= $a^{2} + 2 a b + b^{2}$

= ${(a + b)}^{2}$

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Similar questions

{(a - b)}^{2}

4 a b

{(a + b)}^{2} - (a - b)^{2} = 4 a b

{(a - b)}^{2} + 4 a b

Simplify :
${(a - b)}^{2} + 4 a b$

(a + b)^{2} + (a - b)^{2} = 2 (a^{2} + b^{2})

(a + b)^{2} - (a - b)^{2} = 4 a b

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