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Question

a b a ×b + a .b 2=

(a) a 2 b 2

(b) a +b 2

(c) a 2+ b 2

(d) 2 a 2 b 2

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Solution

a a2b2We havea b a×b + a.b2=a×b . a×b + a.b2=a×b2+ a.b2= ab sin θ2 + a b cos θ2=a2b2 sin2θ + a2b2 cos2θ=a2b2sin2θ + cos2θ =a2b2

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