You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Central Atom and Ligands

A, B and C ar...

Question

A, B and C are three complexes of chromium (III) with the emperical formula $C r (H_{2} O)_{6} C l_{3}$ . These complexes have either water or water and chloride ions as ligands. Complex A does not react with concentrated $H_{2} S O_{4}$ , whereas complexes B and C loose 6.75% and 13.5% of their orignal mass respectively on treatment with conc. $H_{2} S O_{4}$ .

B =

[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C =

[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The conductivity produced by complex B is more than that of complex C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A, B and C are hydration isomers and produce 1, 2 and 3 moles of

A g C l

on reaction with

A g N O_{3}

respectively.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A B = $[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O$
C The conductivity produced by complex B is more than that of complex C
A = $[C r (H_{2} O)_{6}] C l_{3}$
$C r (H_{2} O)_{6} C l_{3} + H_{2} S O_{4} \to N o r e a c t i o n$
Because in it all $H_{2} O$ molecules are present in coordination sphere.

B = $[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O$

$[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O + H_{2} S O_{4} \to o n e m o l e c u l e o f H_{2} O i s r e m o v e d$
Because 1 $H_{2} O$ molecule is present outside the coordination sphere
Molecular weight of complex = 266.5
% loss = $\frac{18}{266.5} \times 100 = 6.75$ %

C = $[C r (H_{2} O)_{4} C l_{2}] C l .2 H_{2} O$
$[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O + H_{2} S O_{4} \to t w o m o l e c u l e s o f H_{2} O i s r e m o v e d$
Because 2 $H_{2} O$ molecules are present outside the coordination sphere
Molecular weight of complex = 266.5
% loss = $\frac{18 \times 2}{266.5} \times 100 = 13.5$ %

$[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O \to [C r (H_{2} O)_{5} C l]^{2 +} (a q .) + 2 C l^{-} (a q .)$
$[C r (H_{2} O)_{4} C l_{2}] C l .2 H_{2} O \to [C r (H_{2} O)_{4} C l_{2}]^{+} (a q .) + C l^{-} (a q .)$
B produces 3 ions on dissociation and C produces 2 ions on dissociation and hence B has more conductivity.

A, B and C are hydration isomers because they have the same molecular formula but different number of $H_{2} O$ molecules inside and outside the coordination sphere.
Also, more the number of $C l^{-}$ ions outside the coordination sphere more the moles of $A g C l$ is formed.

$[C r (H_{2} O)_{6}] C l_{3} + A g N O_{3} \to 3 A g C l$
$[C r (H_{2} O)_{5} C l] C l_{2} . H_{2} O + A g N O_{3} \to 2 A g C l$
$[C r (H_{2} O)_{4} C l_{2}] C l .2 H_{2} O + A g N O_{3} \to A g C l$

Suggest Corrections

Similar questions

A, B and C are three complexes of chromium (III) with the empirical formula

H_{12} O_{6} C l_{3} C r

. All the three complexes have water and chloride ions as ligands. Complex A does not react with concentrated

H_{2} S O_{4}

, whereas complexes B and C lose 6.75% and 13.5% of their original weight respectively, on treatment with concentrated

H_{2} S O_{4}

Thus, select the correct statement :

A, B and C are three complexes of chromium (III) with the empirical formula

H_{12} O_{6} C l_{3} C r

. All the three complexes have water and chloride ions as ligands. Complex A does not react with concentrated

H_{2} S O_{4}

, whereas complexes B and C lose 6.75% and 13.5% of their original weight respectively, on treatment with concentrated

H_{2} S O_{4}

Thus, loss in weight on treatment with concentrated

H_{2} S O_{4}

is due to :

A, B

and

C

are three complexes of chromium(III) with the empirical formula:

H_{12} O_{6} C l_{3} C r

. All the three complexes have water and chloride ions as ligands. Complex

A

does not react with concentrated

H_{2} S O_{4}

, whereas complexes

B

and

C

lose

6.75 %

and

13.5 %

of their original weight, respectively, on treatment with concentrated

H_{2} S O_{4}

. If

C

[C r (H_{2} O)_{x} C l_{y}] C l \cdot z H_{2} O,

find the x, y and z.

Q. One mole of a complex compound

C o (N H_{3})_{5} C l_{3}

gives three moles of ions on dissolution in water. One mole of the same complex reacts with two moles of

A g N O_{3}

and yields two moles of

A g C l (s)

. The complex is:

Q. Which isomer of

C r C l_{3} .6 H_{2} O

is dark green in colour and forms one mole of AgCl with excess of

A g N O_{3}

solution -

Join BYJU'S Learning Program