A, B and C are three metals with atomic number 4, 11, 13 respectively. Arrange the metals in the increasing order of their valency.

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Solution

$A t o m i c n u m b e r o f A, B a n d C a r e A = 4 - E l e c t r o n i c c o n f i g u r a t i o n - 2, 2 - V a l e n c y 2 B = 11 - E l e c t r o n i c c o n f i g u r a t i o n - 2, 8, 1 - V a l e n c y 1 C = 13 - E l e c t r o n i c c o n f i g u r a t i o n - 2, 8, 3 - V a l e n c y 3$
So the order of valency is
B < A < C

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Three elements 'X', 'Y' , 'Z' having atomic number 11, 7 , 6 respectively react with oxygen to form their iroxides .

Arrange these oxides in increasing order of their basic nature.

Match the atomic number 4, 8, 14, 15 and 19 with each of the following:

(a) A solid non-metal of valency 3.

(b) A gas of valency 2.

(d) A non-metal of valency 4.

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