Question

Three metals $A,B$ and $C$ are arranged in increasing order of standard reduction electrode potential, hence their chemical reactivity order will be:

• A. $A<B<C$
• B. $A>B>C$
• C. $B>C>A$
• D. $A=B=C$

Answer 1

The correct option is A $A<B<C$

More negative the standard potential, least the tendency of the cation to be reduced. The corresponding atom has larger tendency for oxidation and hence larger reducing power.

The order is $A<B<C$.