A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in how many days?

1/24 day

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7/24 day

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24/7 days

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4 days

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None of these

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Solution

The correct option is C
24/7 days

(A+B+C)’s 1 day’s work = $(\frac{1}{24} + \frac{1}{6} + \frac{1}{12}) = \frac{7}{24}$

So, A, B and C together will complete the job in $\frac{24}{7}$ days.

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A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in how many days?

The correct option is C 24/7 days (A+B+C)’s 1 day’s work = (124 + 16 + 112) = 724 So, A, B and C together will complete the job in 247 days.

The correct option is C
24/7 days

(A+B+C)’s 1 day’s work = $(\frac{1}{24} + \frac{1}{6} + \frac{1}{12}) = \frac{7}{24}$

So, A, B and C together will complete the job in $\frac{24}{7}$ days.