$A, B$ and $C$ can complete a work separately in $24, 36$ and $48$ days respectively. They started together but $C$ left after $4$ days of start and $A$ left $3$ days before the completion of the work. In how many days will the work be completed ?

15

days

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

22

days

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25

days

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35

days

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $15$ days
Let the total work be W
⇒Speed of A $= \frac{W}{24}$

⇒Speed of B $= \frac{W}{36}$
⇒Speed of C $= \frac{W}{48}$
Let the work takes x days .
Then
$\frac{W}{48} \times 4 + \frac{W}{24} \times (x - 3) + \frac{W}{36} \times x = W$
⇒ Solving we get $x = 15$ days

Suggest Corrections

Similar questions

Q. A ,B and C can do a piece of work in 15,12 and 20 days respectively they started the work together but c left after 2 days .in how many days will the remaining work be completed by a and b?

Q. A, B and C can alone complete a work in 10, 12 and 15 days respectively. A and C started the work and after working for 4 days, A left and B joined. In how many days the total work was completed?

A, B and C can separately do a work in 12, 15 and 20 days respectively. They started to work together but C left after 2 days. The remaining work will be finished in how many days?

Q. A,B and C can complete a work in

6, 12

, and

18

days respectively. A and B started the work and C joined them after one day.B left

2

days before the work complete.Find number of days they all work together.

Q. A alone can do a piece of work in 10 days and B alone can do the same work in 15 days. They started working together. After two days, both of them left the work. If C alone can complete the remaining work in 5 days, then in how many days can C alone complete the work?

A,B and C can complete a work separately in 24,36 and 48 days respectively. They started together but C left after 4 days of start and A left 3 days before the completion of the work. In how many days will the work be completed ?

The correct option is A 15 daysLet the total work be W⇒Speed of A =W24⇒Speed of B =W36⇒Speed of C =W48Let the work takes x days .Then W48×4+W24×(x−3)+W36×x=W⇒ Solving we get x=15 days

$A, B$ and $C$ can complete a work separately in $24, 36$ and $48$ days respectively. They started together but $C$ left after $4$ days of start and $A$ left $3$ days before the completion of the work. In how many days will the work be completed ?

The correct option is A $15$ days
Let the total work be W
⇒Speed of A $= \frac{W}{24}$

⇒Speed of B $= \frac{W}{36}$
⇒Speed of C $= \frac{W}{48}$
Let the work takes x days .
Then
$\frac{W}{48} \times 4 + \frac{W}{24} \times (x - 3) + \frac{W}{36} \times x = W$
⇒ Solving we get $x = 15$ days