A, B and C can do a piece of work in 80 days. If A is twice as efficient as B who is twice as efficient as C, then in how many days C alone takes to complete the work?

360

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480

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560

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600

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640

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Solution

The correct option is C
560

Let the time taken by A to complete the work = x

The time taken by B to complete the work = 2x days

The time taken by C to complete the work = 4x days

If they work together

$\frac{1}{x} + \frac{1}{2 x} + \frac{1}{4 x} = \frac{1}{80}$

$x = 140$

∴ Time taken by C to complete the work = 560 days

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A, B and C can do a piece of work in 80 days. If A is twice as efficient as B who is twice as efficient as C, then in how many days C alone takes to complete the work?

The correct option is C 560 Let the time taken by A to complete the work = x The time taken by B to complete the work = 2x days The time taken by C to complete the work = 4x days If they work together 1x+12x+14x=180 x=140 ∴ Time taken by C to complete the work = 560 days