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Question

A. B and C together can do a piece of work in 40 days. After working with B and C for 16 days, A leaves and then B and C complete the remaining work in 40 days more. A alone could do the work in

A
80 days
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B
90 days
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C
100 days
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D
120 days
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Solution

The correct option is B 100 days
Let the total work be 80 units. [LCM of 40 and 16]
(A + B + C) do = 8040 = 2 units/day
(A + B + C) work for 16 days, complete 16× 2 = 32 units of work
Work left is 8032=48 units.
B and C do = 4840 =1210 = 1.2 units/day
A does = 21.2 units = 0.8 unit/day
A will complete the work in = 800.8 = 100 days

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