A,B,C and D are four coils of wires of 2, 2, 2 and 3 ohm resistances respectively and are arranged to form a Wheatstone bridge.The resistance which the coil 'D' must be shunted in order that the bridge may be balanced is:

Ω

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Solution

The correct option is C 6 $Ω$
Wheatstone condition

$\frac{R_{A}}{R_{C}} = \frac{R_{B}}{R_{D}}$

$R_{B} = R_{D}$

$R_{B} = \frac{3 \times R_{S}}{3 + R_{S}}$

$6 + 2 R_{S} = 3 R_{S}$

$R_{S} = 6 Ω$

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A,B,C and D are four coils of wires of 2, 2, 2 and 3 ohm resistances respectively and are arranged to form a Wheatstone bridge.The resistance which the coil 'D' must be shunted in order that the bridge may be balanced is:

The correct option is C 6ΩWheatstone conditionRARC=RBRDRB=RDRB=3×RS3+RS6+2RS=3RSRS=6Ω

The correct option is C 6 $Ω$
Wheatstone condition

$\frac{R_{A}}{R_{C}} = \frac{R_{B}}{R_{D}}$

$R_{B} = R_{D}$

$R_{B} = \frac{3 \times R_{S}}{3 + R_{S}}$

$6 + 2 R_{S} = 3 R_{S}$

$R_{S} = 6 Ω$