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Question

a,b,c,dR such that a2+b2=4 and c2+d2=2 and if (a+ib)2=(c+id)2(x+iy) then x2+y2=

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Solution

Given that (a+ib)2=(c+id)2(x+iy)
Taking modulus both the sides
|(a+ib)2|=|(c+id)2(x+iy)|
[|z1z2|=|z1||z2|,|zn|=|z|n]
|a+ib|2=|c+id|2|x+iy|
a2+b2=(c2+d2)x2+y2
Given that a2+b2=4,c2+d2=2
4=2x2+y2
x2+y2=4

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