CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If xiy=aibcid prove that x2+y2=a2+b2c2+d2.

Open in App
Solution

Given,

xiy=aibcid

x+iy=a+ibc+id

(xiy)(x+iy)=aibcid×a+ibc+id

x2(iy)2=a2(ib)2c2(id)2

x2+y2=a2+b2c2+d2

Hence proved.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Conjugate of a Complex Number
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon