$A + B ⟶ C; Δ H = + 60 K J / m o l$
$E_{a t}$ is $150$ kj. What is the activation energy for the backward reation?

210

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105

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90

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145

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Solution

The correct option is D $90$ kJ
The Reaction is a Endothermic Reaction. So,

$[E_{a (f)}] - [E_{b (f)}] = Δ H$

$[E_{b (f)}] = 150 - 60 k J$ = $90 k J$

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A+B⟶C;ΔH=+60KJ/molEat is 150 kj. What is the activation energy for the backward reation?

The correct option is D 90kJThe Reaction is a Endothermic Reaction. So,[Ea(f)]−[Eb(f)]=ΔH[Eb(f)]=150−60 kJ = 90 kJ

$A + B ⟶ C; Δ H = + 60 K J / m o l$
$E_{a t}$ is $150$ kj. What is the activation energy for the backward reation?

The correct option is D $90$ kJ
The Reaction is a Endothermic Reaction. So,

$[E_{a (f)}] - [E_{b (f)}] = Δ H$

$[E_{b (f)}] = 150 - 60 k J$ = $90 k J$