A bag contains 1 red ball, 1 green ball, 2 blue balls, and 1 black ball. If a ball is drawn out of the bag, the probability of getting a ball of each colour is equally likely.

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B
False

$Probability = \frac{no. of favorable outcomes}{total no. of outcomes}$

Therefore, the probability of getting a blue ball $= \frac{2}{5}$

Probability of getting a black ball $= \frac{1}{5}$
Probability of getting a green ball $= \frac{1}{5}$

So, the events are not equally likely.

Suggest Corrections

Similar questions

A bag contains 1 red ball, 1 green ball, 2 blue balls and 1 black ball. What is the probability of getting a white ball?

A bag contains 2 red balls, 4 blue balls and 8 green balls. Fatima draws 2 balls out of the bag. What is the probability that she gets a green ball and a blue ball?

Q. A bag contains 4 green balls, 4 red balls and 2 blue balls. If a ball is drawn from the bag, the
probability of getting neither green nor red ball is

(a)

\frac{2}{5}

(b)

\frac{1}{2}

(c)

\frac{4}{5}

(d)

\frac{1}{5}

A bag contains 5 red , 4 green and 3 blue balls. If a ball is drawn at random, what is the probability of getting a red ball

Q. A bag contains

5

red balls,

7

black balls and

8

green balls. A ball is drawn randomly from the bag, the probability of getting a red ball is 1/m then the value of

m

is :

Join BYJU'S Learning Program

A bag contains 1 red ball, 1 green ball, 2 blue balls, and 1 black ball. If a ball is drawn out of the bag, the probability of getting a ball of each colour is equally likely.

The correct option is B False Probability=no. of favorable outcomestotal no. of outcomes Therefore, the probability of getting a blue ball =25 Probability of getting a black ball =15 Probability of getting a green ball =15 So, the events are not equally likely.