Question

A bag contains $10$ red balls,$16$ white balls and $8$ green balls. A ball is drawn out of the bag at random. What is the probability that the ball drawn will be not red?

Answer 1

Total number of possible outcomes $=10+16+8=34$ balls

So, $n\left(S\right)=34$

Favorable outcomes for not a red ball = favorable outcomes for white or green ball

So, number of favorable outcomes for white or green ball $=16+8=24=n\left(E\right)$

Hence, probability for not drawing a red ball $=n\left(E\right)/n\left(S\right)=24/34=12/17$