A bag contains 10 red balls,16 white balls, and 8 green balls. A ball is drawn out of the bag at random. What is the probability that the ball drawn will be white or green?
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Solution
Total number of possible outcomes =10+16+8=34 balls
So, n(S)=34
Number of favorable outcomes for white or green ball =16+8=24=n(E)
Hence, probability for drawing a white or green ball =n(E)/n(S)=24/34=12/17