Question

A bag contains 25 tickets, numbered from 1 to 25. A ticket is drawn and then another ticket is drawn without replacement. Find the probability that both tickets will show even numbers.

Answer 1

There are 12 even numbers between 1 to 25.

Consider the given events.
A = An even number ticket in the first draw
B = An even number ticket in the second draw

$$\begin{gathered} \mathrm{Now}, \\ P\left(A\right)=\frac{12}{25} \\ P\left(B/A\right)=\frac{11}{24} \\ \therefore \mathrm{Required}\mathrm{probability}=P\left(A\cap B\right)=P\left(A\right)\times P\left(B/A\right)=\frac{12}{25}\times \frac{11}{24}=\frac{11}{50} \end{gathered}$$