A bag contains 4 black balls, 5 red balls and 1 blue ball. Probability of picking up a black ball is

0.2

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0.5

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\frac{1}{10}

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\frac{1}{100}

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Solution

The correct option is C $\frac{1}{10}$
We know that,

$p r o b a b i l i t y = \frac{N o . o f f a v o u r a b l e o u t c o m e s}{T o t a l N o . o f o u t c o m e s} = \frac{5}{5 + 4 + 1} = \frac{5}{10} = \frac{1}{2} o r 0.5$

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A bag contains 4 black balls, 5 red balls and 1 blue ball. Probability of picking up a black ball is

The correct option is C 110 We know that, probability =No. of favourable outcomesTotal No. of outcomes = 55+4+1 = 510 = 12 or 0.5

The correct option is C $\frac{1}{10}$
We know that,

$p r o b a b i l i t y = \frac{N o . o f f a v o u r a b l e o u t c o m e s}{T o t a l N o . o f o u t c o m e s} = \frac{5}{5 + 4 + 1} = \frac{5}{10} = \frac{1}{2} o r 0.5$