A bag contains 4 red and 8 blue marbles. A marble is drawn at random. The probability of drawing red is

True

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False

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$\frac{2}{3}$

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$\frac{1}{8}$

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Solution

The correct option is B
False

Given

Number of red marbles = $4$

Number of bluemarbles = $8$

Events favouring n(E) = 4

Total number of outcomes n(S) = 12

Probability of an event occuring P(E) = $\frac{E v e n t s f a v o u r i n g n (E)}{T o t a l n u m b e r o f o u t c o m e s n (S)}$

So, the probability of drawing red is $\frac{4}{12}$ = $\frac{1}{3}$

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