A bag contains $4$ white balls, $6$ red balls, $7$ black balls and $3$ blue balls. One ball is drawn at random from the bag. Find the probability that the ball drawn is not black.

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Solution

Step 1: Finding the probability that the ball drawn is not black.
There are $4$ white balls, $6$ red balls, $7$ black balls and $3$ blue balls.
So, the total outcomes are $20$ .
As there are $7$ black balls, the favorable outcomes will be the sum of all balls except black.
$4 + 6 + 3 = 13$
The formula to compute the probability is expressed as,
$P r o b a b i l i t y = \frac{N o o f f a v o r a b l e o u t c o m e s}{T o t a l o u t c o m e s}$
Substitute the number of favorable outcomes as $13$ and the total outcomes as $20$ in the formula.
$∴ P (n o t a b l a c k b a l l) = \frac{13}{20}$
Therefore, the probability that the ball drawn is not black is $\frac{13}{20}$ .

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