Question

A bag contains $5$ white balls, $7$red balls, $4$ black balls and $2$ blue balls. One ball is drawn at random from a bag. What is the probability that ball drawn is not white?

Answer 1

Step 1 Determining the probability:

Given that a bag contains $5$ white balls, $7$red balls, $4$ black balls and $2$ blue balls.

So, the total number of outcomes

$=5+7+4+2=18$

We have to find the probability of not getting a white ball.

So, the total number of favorable outcomes

$=red+black+blue=7+4+2=13$

The formula for probability is

$$\begin{gathered} Probabilty=\frac{Numberoffavorableoutcomes}{Totalnumberofoutcomes} \\ \therefore P\left(notwhiteball\right)=\frac{13}{18} \end{gathered}$$

Hence, the probability of not getting a white ball is $\frac{13}{18}$.